But if we use it with the + operator, then it will be subtracted from the input date/time. If we use a negative value with the - operator, then the specified number of minutes will be added to the input date/time. It’s possible to perform date arithmetic with negative values. If the minutes to be subtracted are in 60 minute increments, we can alternatively use hours: SELECT time '15:45' - interval '1 hour' We can alternatively subtract the equivalent number in seconds: SELECT time '15:45' - interval '120 seconds' We can also add a date and time value together, and subtract minutes from that: SELECT date '' + time '01:00' - interval '18 minutes' We can even subtract minutes from a date value: SELECT date '' - interval '12 minutes' We can also subtract minutes from an interval: SELECT interval '5 hours' - interval '90 minutes' So to subtract one or more minutes, we can use minute or minutes: SELECT time '07:00' - interval '1 minute' Īnd in plural form: SELECT time '07:00' - interval '45 minutes' Īnd here it is with a timestamp value: SELECT timestamp ' 09:00' - interval '30 minutes' We can specify intervals when performing arithmetic against dates and times. ![]() We can also subtract minutes from a date value or a date and time combination. Now we have the difference between two datetime objects within several different time frames.In PostgreSQL, we can use the - operator to subtract one or more minutes from a time value.īy “time” value, this could be an actual time value, a timestamp, or an interval. Output: The difference in seconds: 1041052966 ![]() Only the quotient is needed, and that’s why only the 0 index is used through the code. The divmod() function accepts two numbers as the dividend and divisor and returns a tuple of the quotient and the remainder between them. In the case of all, it will return an output that gets the difference based on all the cases from years to seconds. The first thing that the code does is to initialize 2 separate dates for subtraction and calling the function multiple times with different outputs each time. Print('The difference in years:', getDifference(then, now, 'yrs')) Print('The difference in days:', getDifference(then, now, 'days')) Print('The difference in hours:', getDifference(then, now, 'hrs')) Print('The difference in minutes:', getDifference(then, now, 'mins')) Print('The difference in seconds:', getDifference(then, now, 'secs')) from datetime import datetimeĭef getDifference(then, now = datetime.now(), interval = "secs"): Here’s the full source code for datetime subtraction using the datetime module and its functions. The datetime object has a built-in method datetime.total_seconds() converting the object into the total seconds it contains.ĭate & Time in Python (Printing and Calculating Date and Time) (Video 53) To convert this result into different formats, we would first have to convert the timedelta into seconds. If you wanted to subtract 5 hours and 15 minutes from the. 2083 from the date-timestamp to subtract 5 hours. So in your case you can simple subtract 5 / 24. ![]() The value to the right of the decimal point are a decimal representation of the 24 hour clock. The result means that the two dates are 12055 days and 5 hours and 10 minutes apart. Value to the left of the decimal point are days. Subtracting two datetime objects will return the difference of the number of days, and the difference in time, if there is any. It also accepts optional parameters in the form of hours, minutes, seconds, microseconds, and timezone.ĭatetime also has the function now(), which initializes the current date and time into the object. Initializing a datetime object takes three required parameters as datetime.datetime(year, month, day). Use the datetime Module to Subtract Datetime in Pythonĭatetime is a module in Python that will support functions that manipulate the datetime object. We will explore different outputs after subtraction, like outputting the number of seconds, minutes, hours, or years of the difference of the two datetime objects provided. This tutorial will introduce how to perform datetime subtraction in Python.
0 Comments
Leave a Reply. |